Imaginary Cube Roots Of 216. If they are then i can just cube. If x 2 6x 36 0 then by the quadratic formula we can show that x is imaginary.
If x 2 6x 36 0 then by the quadratic formula we can show that x is imaginary. 216 is said to be a perfect cube because 6 x 6 x 6 is equal to 216. What are the imaginary cube roots of 216.
If they are then i can just cube.
Now let s assume that the cube roots z are of the form r cosine theta plus i sine theta that is let s assume they re all in trig form. There are no more real ones and no imaginary or complex ones. What are the imaginary cube roots of 216. Remember the cube root of 8i would be a number that when cubed gives you 8i so all the cube roots have to satisfy this equation so i m looking for solutions to this equation.